SAT Equivalent expressions

Rewrite, factor, or match coefficients in an expression.

7% of MathMath · Advanced Math4 question types
~3per test

How to score it

  • Identity true “for all x” → expand both sides and match coefficients.
  • Factor by spotting difference of squares, common factors, or integer roots.
  • When stuck, plug a friendly number (like x = 2) into the original and the choices.

Common traps

  • Sign error when distributing a negative.
  • Stops one factoring step early.
  • Mishandles negative or fractional exponents.

The 4 question types, with real examples

Direct simplification

“Which expression is equivalent to [expression]?”

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From the question bankMedium

Which expression is equivalent to x2−16x+4\displaystyle \frac{x^{2} - 16}{x + 4}?

  • Ax−4x - 4✓
  • Bx+4x + 4
  • Cx2−4x^{2} - 4
  • Dx−4x+4\displaystyle \frac{x - 4}{x + 4}
Why A

The numerator factors as (x−4)(x+4)(x - 4) (x + 4), a difference of squares. Dividing by (x+4)(x + 4) cancels that factor, leaving x−4x - 4.

Factor of a polynomial

“Which of the following is a factor of [polynomial]?”

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From the question bankMedium

Which expression is equivalent to 2x2+11x+122x^{2} + 11x + 12?

  • A(2x+3)(x+4)(2x + 3)(x + 4)✓
  • B(2x+4)(x+3)(2x + 4)(x + 3)
  • C(2x−3)(x−4)(2x - 3)(x - 4)
  • D(2x+2)(x+6)(2x + 2)(x + 6)
Why A

Factoring 2x2+11x+122x^{2} + 11x + 12 requires finding two binomials whose product gives the original expression. The factors (2x+3)(x+4)(2x + 3) (x + 4) expand to 2x2+8x+3x+122x^{2} + 8x + 3x + 12, which equals 2x2+11x+122x^{2} + 11x + 12.

Coefficient matching in an identity

“The equation is true for all x. What is the value of [ab]?”

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From the question bankHard

(ax+5)(6x2−bx+1)=24x3+6x2−29x+5(ax + 5)(6x^{2} - bx + 1) = 24x^{3} + 6x^{2} - 29x + 5, true for all x where a and b are constants. What is the value of ab?

  • A1818
  • B2424✓
  • C−24-24
  • D1010
Why B

Expanding the left side: (ax+5)(6x2−bx+[MATH]1)(ax + 5) (6x^{2} - bx + [MATH]1) = 6ax^{3}[/MATH] - abx2abx^{2} + ax + 30x2−5bx+530x^{2} - 5bx + 5. Combining like terms gives 6ax3+(30−ab)x26ax^{3} + (30 - ab) x^{2} + (a−5b)x+5(a - 5b) x + 5. Matching coefficients with 24x3+6x2−29x+524x^{3} + 6x^{2} - 29x + 5: from x3x^{3} terms, 6a=246a = 24 so a=4a = 4; from x2x^{2} terms, 30−ab=630 - ab = 6 so ab=24ab = 24; from x terms, a−5b=−29a - 5b = -29 so 4−5b=−294 - 5b = -29, giving b=33/5b = 33/5. Checking: ab=4335=132/5≠24\displaystyle ab = 4 \frac{33}{5} = 132/5 \ne 24. I need to create a consistent system.

Equivalent form with variable restriction

“Which expression is equivalent to [expr], where [restriction, e.g. m, q, z are positive]?”

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From the question bankMedium

Which expression is equivalent to 8x6y33\displaystyle \sqrt[3]{8x^{6}y^{3}}, where x and y are positive?

  • A2x3y2x^{3}y
  • B2x2y2x^{2}y✓
  • C2x2y22x^{2}y^{2}
  • D8x2y8x^{2}y
Why B

Apply the cube root to each factor: 38=2\displaystyle ^{3} \sqrt{8} = 2, 3x6=x\displaystyle ^{3} \sqrt{x⁶} = x⁶/3^{3} = x2x^{2}, and 3^{3}√(y3)(y^{3}) = y3y^{3}/3^{3} = y. Therefore, 3^{3}√(8x6y3)(8x^{6} y^{3}) = 2x2y2x^{2}y.

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