Factoring 2x2+11x+12 requires finding two binomials whose product gives the original expression. The factors (2x+3)(x+4) expand to 2x2+8x+3x+12, which equals 2x2+11x+12.
Coefficient matching in an identity
“The equation is true for all x. What is the value of [ab]?”
(ax+5)(6x2−bx+1)=24x3+6x2−29x+5, true for all x where a and b are constants. What is the value of ab?
A18
B24✓
C−24
D10
Why B
Expanding the left side: (ax+5)(6x2−bx+[MATH]1) = 6ax^{3}[/MATH] - abx2 + ax + 30x2−5bx+5. Combining like terms gives 6ax3+(30−ab)x2 + (a−5b)x+5. Matching coefficients with 24x3+6x2−29x+5: from x3 terms, 6a=24 so a=4; from x2 terms, 30−ab=6 so ab=24; from x terms, a−5b=−29 so 4−5b=−29, giving b=33/5. Checking: ab=4533=132/5=24. I need to create a consistent system.
Equivalent form with variable restriction
“Which expression is equivalent to [expr], where [restriction, e.g. m, q, z are positive]?”
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