Free video lesson

How to Simplify Complex Numbers on the SAT

The letter i makes complex numbers look scary, but there's really only one new fact: i squared equals negative one. This lesson shows how every SAT complex-number question reduces to ordinary algebra. Multiply with FOIL and swap i squared for negative one, divide using the conjugate, and simplify powers of i with the four-step cycle. Worked example, the conjugate trick, a your-turn problem, and the three traps that cost points.

Math · Equivalent expressions4:05Published July 19, 2026

On YouTube: SAT Complex Numbers: It All Comes Back to i Squared

What this lesson covers

  • i squared equals negative one (replace it everywhere)
  • To divide, multiply top and bottom by the denominator's conjugate
  • Powers of i cycle every 4: use the remainder mod 4

Chapters

Lesson transcript

The narration of the video, word for word, under its chapter headings.

0:00The one fact that runs everything

Welcome to SAT Climb. Complex numbers look scary because of that letter i. But here's the secret. There is really only one new fact. i squared equals negative one. Master that single substitution, and every complex-number question on the digital SAT becomes ordinary algebra.

0:23i squared and the cycle of four

Start with the definition. i is the square root of negative one, so i squared is negative one. From that, the powers of i fall into a cycle that repeats every four. i to the first is i. i squared is negative one. i cubed is negative i. i to the fourth is one. Then it starts over. That four-step cycle, and the substitution i squared equals negative one, are the entire toolkit.

0:55Multiply: FOIL, then swap i squared

Let's use it. Multiply three plus two i, times one plus four i. FOIL it exactly like a normal binomial. Three times one is three. Three times four i is twelve i. Two i times one is two i. Two i times four i is eight i squared. Now the only new move. Replace i squared with negative one. So eight i squared becomes negative eight. Combine the real parts, three minus eight, negative five. Combine the imaginary parts, twelve i plus two i, fourteen i. The answer is negative five plus fourteen i. Same FOIL you already know, one substitution at the end.

1:41Divide: use the conjugate

What if you're dividing? You can't leave i in the denominator. The trick is the conjugate. Take the bottom, one minus two i, and flip the sign on the i term to get one plus two i. Multiply top and bottom by that. Watch the bottom. One minus two i, times one plus two i, is one minus four i squared, which is one plus four, five. A real number. The i vanished. The top works out to negative four plus seven i. So the answer is negative four fifths plus seven fifths i. The conjugate always clears the bottom, because a minus b i times a plus b i is a squared plus b squared.

2:31Your turn: powers of i

Your turn. Simplify i to the twenty-second power. Don't multiply it out twenty-two times. The powers cycle every four, so all that matters is the remainder when you divide the exponent by four. Twenty-two divided by four is five, remainder two. So i to the twenty-second is the same as i squared, which is negative one. Remainder two, answer negative one.

3:09Three traps

Three traps. One, forgetting the substitution. If i squared is still sitting in your answer, you're not done. Replace it with negative one. Two, botching the conjugate. Flip the sign on the imaginary term only. One minus two i becomes one plus two i, not negative one plus two i. Three, powers of i. Divide the exponent by four and use the remainder, never the exponent itself. Everything traces back to i squared equals negative one.

3:43Recap

Complex numbers, solved. Multiply like normal, then swap every i squared for negative one. To divide, hit the bottom with its conjugate. And powers of i just cycle every four. Start practicing free at satclimb.com. Your SAT is closer than you think.

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