SAT Systems of two linear equations

Solve two equations at once — often for a clever combination.

6% of MathMath · Algebra4 question types
~3per test

How to score it

  • If they ask for x + y or 2x − y, try adding or subtracting the equations directly — you may skip solving entirely.
  • Context problems: define two variables, write two equations, eliminate.
  • “No solution” = same slope, different intercept (parallel lines).

Common traps

  • Solves fully when adding the equations gives the answer instantly.
  • “No solution” treated as “solve it” instead of matching coefficients.
  • Mixes up which variable the question wants.

The 4 question types, with real examples

Solve, return a derived value

The solution is (x, y). What is the value of [x + y / xy / 2x − y]?

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From the question bankMedium

y=5x7y = 5x - 7 4x+y=294x + y = 29 The solution to the given system of equations is (x, y). What is the value of 3x?

  • A44
  • B88
  • C12-12
  • D1212
Why D

Substituting y=5x7y = 5x - 7 into the second equation yields 4x+5x7=294x + 5x - 7 = 29, or 9x=369x = 36. Solving gives x=4x = 4. Therefore, 3x=123x = 12.

Context: two prices, two purchases

[Person A bought …; Person B bought …] How many [items] … ?

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From the question bankMedium

Sophia bought 3 notebooks and 5 pens for $18.45. Diego bought 2 notebooks and 3 pens for $11.70. How many notebooks are in Diego's purchase?

  • A33
  • B55
  • C22
  • D11
Why C

Let n be the price of one notebook and p be the price of one pen. From the given information: 3n+5p=18.453n + 5p = 18.45 and 2n+3p=11.702n + 3p = 11.70. Solving this system yields n=2.85n = 2.85 and p=1.80p = 1.80. The question asks how many notebooks are in Diego's purchase, which is stated directly in the problem as 2.

Constant for no / infinite solutions

If the system has no solution, what is the value of [parameter]?

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From the question bankHard

4x+3y=244x + 3y = 24 8xky=128x - ky = 12 For what value of k will the system of equations above have no solution?

  • A12-12
  • B6-6
  • C66
  • D33
Why B

For no solution, the lines must be parallel but distinct. The x-coefficients have ratio 8/4 = 2, so multiplying the first equation by 2 gives 8x+6y=488x + 6y = 48. For parallel lines, we need 8x - ky = 12 to have k=6-k = 6, so k=6k = -6. The constant terms differ (4812)(48 \ne 12), confirming no solution.

Identify a point that lies on both lines

For each real number r, which of the following points lies on the graph of each equation in the xy-plane for the given system?

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From the question bankMedium

y=2xry = 2x - r y=x+7y = x + 7

For each real number r, which of the following points lies on the graph of each equation in the xy-plane for the given system?

  • A(7+r,14+r)(7 + r, 14 + r)
  • B(7r,14r)(7 - r, 14 - r)
  • C(7+r,7)(7 + r, 7)
  • D(7+r2,14+r2)\displaystyle (\frac{7 + r}{2}, \frac{14 + r}{2})
Why A

Setting the equations equal: 2xr=x+72x - r = x + 7, so x=7+rx = 7 + r. Substituting into y=x+7y = x + 7 gives y=(7+r)+7=14+ry = (7 + r) + 7 = 14 + r.

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