20 easy SAT Probability & conditional probability questions

These are the questions most test-takers get right. They are worth practising anyway: on the digital SAT the easy questions in Module 1 are what route you into the harder, higher-scoring Module 2, so dropping one costs more than it looks.

Every question below is a real item from the SAT Climb bank, tagged easy by the same difficulty model the app uses to build your practice. Pick an answer before you open the explanation.

Math · Problem-Solving and Data Analysis~2 per testEasy tier
Question 1Easy

A survey of 50 students asked whether they prefer basketball or soccer. Of the students surveyed, 18 prefer basketball and 32 prefer soccer. If one of these students is selected at random, what is the probability of selecting a student who prefers basketball?

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Why B is right

The probability of selecting a student who prefers basketball is the number of students who prefer basketball divided by the total number of students surveyed. There are 18 students who prefer basketball out of 50 total students, so the probability is 18/50.

Why the others are wrong

  • AThis uses 32 (the number of students who prefer soccer) as the denominator instead of the total number of students.
  • CThis uses the count of students who prefer soccer (32) as the numerator instead of those who prefer basketball.
  • DThis incorrectly uses 50 as both numerator and denominator, representing certainty rather than the actual probability.
Question 2Easy

Each face of a fair 18-sided die is labeled with a number from 1 through 18, with a different number appearing on each face. If the die is rolled one time, what is the probability of rolling a number greater than 15?

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Why C is right

The numbers greater than 15 on an 18-sided die are 16, 17, and 18, which is 3 numbers. The probability is the number of favorable outcomes divided by the total number of outcomes, which is 3/18.

Why the others are wrong

  • AThis incorrectly assumes only 1 number satisfies the condition instead of counting all numbers greater than 15.
  • BThis incorrectly uses 2 as the numerator, possibly confusing the difference between 18 and 15 with the count of favorable outcomes.
  • DThis incorrectly uses 15 (the threshold value) as the numerator instead of counting the numbers that are greater than 15.
Question 3Easy

A class has 25 students: 14 students have brown hair, 6 students have blonde hair, and 5 students have black hair. If one student is selected at random from the class, what is the probability of selecting a student with brown hair?

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Why B is right

The probability of selecting a student with brown hair is the number of students with brown hair divided by the total number of students. There are 14 students with brown hair out of 25 total students, so the probability is 14/25.

Why the others are wrong

  • AThis uses 11 as the numerator, which is the count of students without brown hair (6 + 5).
  • CThis uses 11 as the denominator, which is the count of students without brown hair rather than the total count.
  • DThis uses 20 as the numerator, which might represent an arithmetic error in adding hair color counts (14 + 6).
Question 4Easy

A jar contains 50 tokens: 18 gold tokens, 15 silver tokens, and 17 bronze tokens. If one token is selected at random from the jar, what is the probability of selecting a silver token?

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Why D is right

The probability of selecting a silver token is the number of silver tokens divided by the total number of tokens. There are 15 silver tokens and 50 total tokens, so the probability is 15/50.

Why the others are wrong

  • AThis uses the wrong denominator of 35 (the number of non-silver tokens) instead of 50 (all tokens).
  • BThis incorrectly uses the number of bronze tokens instead of silver tokens in the numerator.
  • CThis incorrectly adds the number of bronze and silver tokens instead of using only silver tokens.
Question 5Easy

A class has 40 students: 15 students who play piano, 13 students who play guitar, and 12 students who play drums. If one student is selected at random from the class, what is the probability of selecting a student who plays drums?

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Why B is right

The probability of selecting a student who plays drums is the number of students who play drums divided by the total number of students. There are 12 students who play drums out of 40 total students, so the probability is 12/40.

Why the others are wrong

  • AThis uses 28 (the number of students who do not play drums) as the denominator instead of the total number of students.
  • CThis uses the count of students who play guitar (13) as the numerator instead of those who play drums.
  • DThis adds piano and guitar players (15 + 13 = 28) but incorrectly uses 25 as the numerator.
Question 6Easy

A container holds 36 blocks: 14 red blocks, 12 yellow blocks, and 10 green blocks. If one block is selected at random from the container, what is the probability of selecting a yellow block?

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Why D is right

The probability of selecting a yellow block is the number of yellow blocks divided by the total number of blocks. There are 12 yellow blocks and 36 total blocks, so the probability is 12/36.

Why the others are wrong

  • AThis incorrectly uses the number of green blocks instead of yellow blocks in the numerator.
  • BThis uses the wrong denominator of 24 (the number of non-yellow blocks) instead of 36 (all blocks).
  • CThis incorrectly adds the number of red and yellow blocks instead of using only yellow blocks.
Question 7Easy

A bag contains 6 red marbles, 4 blue marbles, and 5 green marbles. If one marble is selected at random from the bag, what is the probability of selecting a red marble?

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Why B is right

The probability of selecting a red marble is the number of red marbles divided by the total number of marbles. There are 6 red marbles and 15 total marbles (6 + 4 + 5 = 15), so the probability is 6/15.

Why the others are wrong

  • AThis incorrectly uses only the number of red marbles as the denominator instead of the total number of marbles.
  • CThis incorrectly adds the number of blue and green marbles (4 + 5 = 9) instead of using the count of red marbles in the numerator.
  • DThis incorrectly uses the sum of blue and green marbles in the numerator instead of just the red marbles.
Question 8Easy

A bag contains 15 marbles: 6 red marbles, 5 blue marbles, and 4 green marbles. If one marble is selected at random from the bag, what is the probability of selecting a red marble?

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Why B is right

The probability of selecting a red marble is the number of red marbles divided by the total number of marbles. There are 6 red marbles and 15 total marbles, so the probability is 6/15.

Why the others are wrong

  • AThis incorrectly uses the number of green marbles instead of red marbles in the numerator.
  • CThis incorrectly adds the number of blue and green marbles instead of using only red marbles.
  • DThis uses the wrong denominator by considering only the non-red marbles (9) instead of all marbles (15).
Question 9Easy

A container holds 40 buttons: 16 small buttons, 14 medium buttons, and 10 large buttons. If one button is selected at random from the container, what is the probability of selecting a large button?

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Why B is right

The probability of selecting a large button is the number of large buttons divided by the total number of buttons. There are 10 large buttons out of 40 total buttons, so the probability is 10/40.

Why the others are wrong

  • AThis incorrectly uses 30 (the count of non-large buttons, 16 + 14) as the denominator instead of the total 40 buttons.
  • CThis incorrectly doubles the number of large buttons, perhaps by adding 10 to itself, resulting in 20 as the numerator.
  • DThis incorrectly uses the count of non-large buttons (16 + 14 = 30) as the numerator instead of large buttons.
Question 10Easy

A company produces light bulbs, and 17 out of every 100 light bulbs produced are defective. If a light bulb produced by this company is selected at random, what is the probability of selecting a defective light bulb?

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Why B is right

It is given that 17 out of every 100 light bulbs are defective. The probability of selecting a defective light bulb is the number of defective bulbs divided by the total number of bulbs, which is 17/100.

Why the others are wrong

  • AThis represents the probability of selecting a light bulb that is not defective.
  • CThis incorrectly uses 83 as the denominator, which represents the number of non-defective bulbs.
  • DThis inverts the correct probability calculation.
Question 11Easy

A box contains 24 pencils: 9 yellow pencils, 7 red pencils, and 8 black pencils. If one pencil is selected at random from the box, what is the probability of selecting a yellow pencil?

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Why A is right

The probability of selecting a yellow pencil is the number of yellow pencils divided by the total number of pencils. There are 9 yellow pencils out of 24 total pencils, so the probability is 9/24.

Why the others are wrong

  • BThis incorrectly uses 15 (the count of non-yellow pencils, 7 + 8) as the denominator instead of the total 24 pencils.
  • CThis incorrectly uses the count of non-yellow pencils (7 + 8 = 15) as the numerator instead of yellow pencils.
  • DThis incorrectly adds an unrelated quantity to 9, perhaps 8, resulting in 17 as the numerator.
Question 12Easy

A box contains 12 red marbles and 8 blue marbles. If one marble is selected at random from the box, what is the probability of selecting a red marble?

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Why B is right

There are 12 red marbles out of a total of 20 marbles in the box. The probability of selecting a red marble is the number of red marbles divided by the total number of marbles, which is 12/20.

Why the others are wrong

  • AThis represents the probability of selecting a blue marble instead of a red marble.
  • CThis incorrectly uses only the counts of red and blue marbles as the denominator, ignoring the total count.
  • DThis inverts the correct probability calculation.
Question 13Easy

A jar contains 30 candies: 12 chocolate candies, 10 mint candies, and 8 fruit candies. If one candy is selected at random from the jar, what is the probability of selecting a mint candy?

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Why A is right

The probability of selecting a mint candy is the number of mint candies divided by the total number of candies. There are 10 mint candies out of 30 total candies, so the probability is 10/30.

Why the others are wrong

  • BThis uses 20 as the denominator, which is the count of non-mint candies (12 + 8) rather than the total count.
  • CThis uses 18 as the numerator, which might represent adding chocolate and fruit candies (12 + 8 - 2) through an arithmetic error.
  • DThis uses 20 as the numerator, which is the count of candies that are not mint (12 + 8).
Question 14Easy

In a deck of 30 cards, 12 cards are labeled A, 10 cards are labeled B, and 8 cards are labeled C. If one card is selected at random from the deck, what is the probability of selecting a card labeled C?

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Why B is right

The probability of selecting a card labeled C is the number of C cards divided by the total number of cards. There are 8 cards labeled C and 30 total cards, so the probability is 8/30.

Why the others are wrong

  • AThis uses the wrong denominator of 22 (the number of non-C cards) instead of 30 (all cards).
  • CThis incorrectly uses the number of B cards instead of C cards in the numerator.
  • DThis incorrectly adds the number of B and C cards instead of using only C cards.
Question 15Easy

A box contains 24 pencils: 9 yellow pencils, 7 red pencils, and 8 blue pencils. If one pencil is selected at random from the box, what is the probability of selecting a blue pencil?

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Why A is right

The probability of selecting a blue pencil is the number of blue pencils divided by the total number of pencils. There are 8 blue pencils out of 24 total pencils, so the probability is 8/24.

Why the others are wrong

  • BThis uses 16 as the denominator, which is the count of non-blue pencils (9 + 7) rather than the total count.
  • CThis uses 15 as the numerator, which might represent adding yellow and red pencils (9 + 7 - 1) through an arithmetic error.
  • DThis uses 16 as the numerator, which is the count of pencils that are not blue (9 + 7).
Question 16Easy

A spinner has 5 equal sections labeled 1 through 5. If the spinner is spun one time, what is the probability of landing on a section labeled with an odd number?

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Why C is right

The odd numbers on the spinner are 1, 3, and 5, which gives 3 odd-numbered sections. The probability of landing on an odd number is 3 favorable outcomes divided by 5 total sections, which is 3/5.

Why the others are wrong

  • AThis represents the probability of landing on an even number instead of an odd number.
  • BThis incorrectly uses 3 as the denominator instead of the total number of sections.
  • DThis inverts the correct probability calculation.
Question 17Easy

A jar contains 30 jellybeans: 11 purple jellybeans, 9 orange jellybeans, and 10 green jellybeans. If one jellybean is selected at random from the jar, what is the probability of selecting a purple jellybean?

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Why C is right

The probability of selecting a purple jellybean is the number of purple jellybeans divided by the total number of jellybeans. There are 11 purple jellybeans and 30 total jellybeans, so the probability is 11/30.

Why the others are wrong

  • AThis incorrectly uses 9, the count of orange jellybeans, instead of 11 purple jellybeans.
  • BThis incorrectly uses 19 as the denominator, which equals the number of non-purple jellybeans (9 + 10).
  • DThis incorrectly adds orange and green jellybeans (9 + 10 = 19) as the numerator.
Question 18Easy

A box contains 30 cards numbered 1 through 30. If one card is selected at random from the box, what is the probability of selecting a card numbered with a multiple of 5?

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Why D is right

The multiples of 5 from 1 to 30 are 5, 10, 15, 20, 25, and 30, which gives 6 favorable outcomes. The probability of selecting a multiple of 5 is 6 divided by 30 total cards, which is 6/30.

Why the others are wrong

  • AThis represents the probability of selecting a card that is not a multiple of 5.
  • BThis incorrectly uses 24 as the denominator, which represents the number of non-multiples of 5.
  • CThis inverts the correct probability calculation.
Question 19Easy

A box contains 30 tokens: 12 silver tokens, 9 gold tokens, and 9 bronze tokens. If one token is selected at random from the box, what is the probability of selecting a bronze token?

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Why B is right

The probability of selecting a bronze token is the number of bronze tokens divided by the total number of tokens. There are 9 bronze tokens and 30 total tokens, so the probability is 9/30.

Why the others are wrong

  • AThis incorrectly uses 21 as the denominator, possibly by adding silver and gold tokens (12 + 9) or subtracting bronze from the total.
  • CThis uses the number of silver tokens (12) as the numerator instead of bronze tokens.
  • DThis adds gold and bronze tokens (9 + 9 = 18) as the numerator, incorrectly combining categories.
Question 20Easy

A bag contains 6 plastic tiles labeled with the letters A, B, C, D, E, and F. If one tile is selected at random from the bag, what is the probability of selecting a tile labeled with a vowel?

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Why C is right

Among the letters A, B, C, D, E, and F, the vowels are A and E, which gives 2 vowels. The probability of selecting a vowel is 2 favorable outcomes divided by 6 total tiles, which is 2/6.

Why the others are wrong

  • AThis represents the probability of selecting a consonant instead of a vowel.
  • BThis incorrectly uses 4 as the denominator, which represents the number of consonants.
  • DThis inverts the correct probability calculation.

What to do after easy

Getting these right quickly is the point: speed on the easy questions is what buys time for the hard ones. When they stop costing you effort, move up.

Questions are written by SAT Climb and drawn from its own item bank. SAT® is a registered trademark of College Board, which is not affiliated with and does not endorse SAT Climb.